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You are given an undirected graph G = (V, E) containing N nodes and M edges. The nodes are numbered from 1 to N. A subset C of V is a vertex cover if for every edge (u, v) ∈ E, at least one of u and v belong to C. Note that C = V is always a vertex cover.
Consider a partition of V into two sets A and B. It is said to be a valid partition, if the following two conditions are satisfied: A should be a vertex cover. And for each i such that 1 ≤ i ≤ n/2, nodes 2*i and 2*i - 1 don't belong to the same set (i.e. one belongs to set A and the other to set B).
Determine if a valid partition exists. If it exists, provide an example of one valid partition.
- The first line of the input contains a single integer T denoting the number of test cases. The description of T test cases follows.
- The first line of each test case contains two space-separated integers N and M denoting the number of nodes and number of edges in the graph respectively.
- Each of the following M lines contains two space-separated integers u and v denoting an edge between nodes u and v.
- For each test case, print a line containing the string "possible" (without quotes) if a solution exists or "impossible" otherwise.
- If a solution exists, print a second line containing a binary string. The i-th character of this string should be '0' if vertex i is in set B or '1' if it is in set A.
- 1 ≤ T ≤ 105
- 1 ≤ N ≤ 2 · 105
- 0 ≤ M ≤ 2 · 105
- 1 ≤ u, v ≤ N
- 1 ≤ sum of N over all test cases ≤ 106
- 1 ≤ sum of M over all test cases ≤ 106
Input: 2 3 2 1 2 2 3 4 5 1 3 2 4 1 4 1 2 2 3 Output: possible 011 impossible
Example case 1: We can put nodes numbered 2 and 3 in set A and node 1 in set B. Note that this is a valid partition because set A is a vertex cover; also, nodes numbered 1 and 2 belong to different sets.
Example case 2: There exists no partition which satisfies the conditions.
|Tags||2-sat, acm17chn, chn17rol, graphs, medium, triveni|
|Time Limit:||3 sec|
|Source Limit:||50000 Bytes|
|Languages:||C, CPP14, JAVA, PYTH, PYTH 3.6, PYPY, kotlin, PYP3|
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