Tweedle-Dee and Tweedle-Dum
All submissions for this problem are available.
Read problems statements in Mandarin Chinese, Russian and Vietnamese as well.
Tweedle-Dee and Tweedle-Dum are in a fierce battle playing even-odd nim. This novel game is played on N heaps. Heap i contains ai stones.
Like normal nim, Tweedle-Dee and Tweedle-Dum alternate taking a positive number of stones from any single one of the heaps, and the player that can't remove stones loses. However Tweedle-Dee can only take an even number of stones, and Tweedle-Dum can only take an odd number of stones.
Alice doesn't want to wait until the end of the game, so she asks you to determine the winner of the game. Remember that Tweedle-Dee and Tweedle-Dum are legendary grandmasters of combinatorial games, so they always play optimally.
The first line of the input contains an integer T denoting the number of test cases. The description of T test cases follows.
The first line of each case consists of an integer N the number of heaps, and a string P the player that starts the game. String P is equal to "Dee" if Tweedle-Dee goes first, or "Dum" if Tweedle-Dum goes first.
The second line of each case contains N space separated integers ai the number of stones of the i-th heap.
For each test case, output a single line containing either "Dee" if Twedle-Dee winns the game or "Dum" otherwise.
- 1 ≤ T ≤ 50
- 1 ≤ N ≤ 50
- 1 ≤ ai ≤ 50
Input: 1 2 Dee 2 2 Output: Dum
Tweedle-Dee takes two stones from any of the heaps leaving just one non empty heap, next Tweedle-Dum takes one stone and the game finishes.
|Tags||alei, cakewalk, cook73, game-theory, parity|
|Time Limit:||1 sec|
|Source Limit:||50000 Bytes|
|Languages:||C, CPP14, JAVA, PYTH, PYTH 3.6, PYPY, CS2, PAS fpc, PAS gpc, RUBY, PHP, GO, NODEJS, HASK, SCALA, D, PERL, FORT, WSPC, ADA, CAML, ICK, BF, ASM, CLPS, PRLG, ICON, SCM qobi, PIKE, ST, NICE, LUA, BASH, NEM, LISP sbcl, LISP clisp, SCM guile, JS, ERL, TCL, PERL6, TEXT, SCM chicken, PYP3, CLOJ, FS|
Fetching successful submissions
If you are still having problems, see a sample solution here.