Puppy and Sum
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Yesterday, puppy Tuzik learned a magically efficient method to find the sum of the integers from 1 to N. He denotes it as sum(N). But today, as a true explorer, he defined his own new function: sum(D, N), which means the operation sum applied D times: the first time to N, and each subsequent time to the result of the previous operation.
For example, if D = 2 and N = 3, then sum(2, 3) equals to sum(sum(3)) = sum(1 + 2 + 3) = sum(6) = 21.
Tuzik wants to calculate some values of the sum(D, N) function. Will you help him with that?
The first line contains a single integer T, the number of test cases. Each test case is described by a single line containing two integers D and N.
For each testcase, output one integer on a separate line.
- 1 ≤ T ≤ 16
- 1 ≤ D, N ≤ 4
Input: 2 1 4 2 3 Output: 10 21
The first test case: sum(1, 4) = sum(4) = 1 + 2 + 3 + 4 = 10.
The second test case: sum(2, 3) = sum(sum(3)) = sum(1 + 2 + 3) = sum(6) = 1 + 2 + 3 + 4 + 5 + 6 = 21.
|Tags||basic-math, cakewalk, cook67, implementation, pavel1996|
|Time Limit:||1 sec|
|Source Limit:||50000 Bytes|
|Languages:||C, CPP14, JAVA, PYTH, PYTH 3.6, PYPY, CS2, PAS fpc, PAS gpc, RUBY, PHP, GO, NODEJS, HASK, SCALA, D, PERL, FORT, WSPC, ADA, CAML, ICK, BF, ASM, CLPS, PRLG, ICON, SCM qobi, PIKE, ST, NICE, LUA, BASH, NEM, LISP sbcl, LISP clisp, SCM guile, JS, ERL, TCL, PERL6, TEXT, SCM chicken, PYP3, CLOJ, FS|
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