CodeChef submission 839491 (C) plaintext list. Status: WA, problem PERMUT2, contest . By codesmart (codesmart), 2012-02-09 03:26:48.
#include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int n,i,flag; int str[100001]; while(1) { flag=0; if(n==0) break; for(i=1;i<=n;i++) { str[str[i]]=i; } for(i=1;i<=n;i++) { if(str[str[i]]!=i) { flag=0; break; } else flag=1; } if(flag==1) } //system("PAUSE"); return 0; }
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