where should i type the code

is notepad ok?

time limit exceeded error for following code......plz help me reduce time consumption

#include<stdio.h>

int main(void)

{

unsigned int num;

for(;printf("%d",scanf("%d",&num)!=42););

return(0);

}

Your program never exits. Your scanf function will never return 42.

why this doesn't get accepted ?

#include <stdio.h>

int main(){

int num=0;

for(;num!=42;printf("%dn", num,scanf("%d", &num)));

return 0;

}

It gives the wrong answer for every single input, including the sample input.

Why ''(backslash) not coming before n in my code?

Is there any technical problem?

The problem is that you aren't meant to post code in comments, which you would know if you had read the FAQ. You will also find the solution to your problem there.

Actually I have doubt with question

After entering all input values the output can listed out (ie) get all values if 42 appears then it print all other values....

eg:

10

20

30

42

o/p 10 20 30

or

if enter one value and it gives output until enter 42

10

10

65

65

42

---->ends

Read the FAQ.

*snip*

what is difference b/w lower code and upper code.....????

lower is correct...

and in upper code case..it prints wrong answer

The upper code starts by printing out "How Many values do you want to input". That is not part of the correct solution, so you get wrong answer. Please read the FAQ.

Why do you insist on posting your code in the comments?

Do you not understand what this site is supposed to be about?

How do we accept input for C++??

Will cin work, or we have to input from file?

I just wrote the solution of this problem in C# and there what was astonishing that i just input, compare and display till 42 is entered.

Time: 0.19 secs

Mem: 11.2M

A lot of solutions in C / C++ does almost the same, but they have a better Time and Memory performance. Is it normal for C# to take more memory and time ?

I am very new to this forum, I wrote this program as the practice, but it gave me runtime error. Could you let me know, what I need to do?

Thanks

You could start by reading the FAQ.

please if anyone can tell me why d codechef compiler is telling  "wrong answer" of this solution..........

need assistance...

d program is giving required output on my cmd.........

You aren't meant to output the word 'output'. You also shouldn't assume there are only 50000 numbers in the input, but you might get lucky and get accepted anyway.

i have also verified Through FAQ i am getting Run Time (Other) i checked with un used variables There arent any :) And memory also i havent declared more than necessary

Please Help

@aweety:dont know the error bt dont use printf("enter the number")  line it will give error on codechef compiler

@sweety:dont know the error bt dont use printf("enter the number")  line it will give error on codechef compiler

Getting Run Time error :(:(

Can some body help please ??

I am able to Execyte perfectly on my Ecllipse

import java.util.Scanner;

public class Main {

public static void main (String args[])

{

int i=1;

int []anArray;

anArray = new int[100];

while (true)

{

Scanner scanner = new Scanner(System.in);

anArray[i] = scanner.nextInt();

if((anArray[i])==42)

{

break;

}

//     System.out.print("n In loop"+i+"n");

i++;

}

//     System.out.print("n After coming out of loop "+i+"n");

for (int pos=1;pos<i;pos++)

{

System.out.println(anArray[pos]);

//     System.out.print("n Printing the value of Pos:"+pos+"n");

}  

}

}

Please read the FAQ (in particular, 'other common mistakes'; same applies to Scanners).

Hi Stephen

i changed the Scanner  and taking input from Buffers Stream ,, It still shows Run Time error

I debugged it and i think i have made sure that its not doint any thng what is mentioned in

FAQ ..

Please Help pasting the modified code

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

public class Main {

public static void main (String args[])

{

int i=0;

int []anArray;

String line=null;

anArray = new int[100];

while (true)

{

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

try {

line=br.readLine();

anArray[i] = Integer.parseInt(line);

System.out.print("n In loop value Stored"+anArray[i]+"n");

} catch (IOException e) {

e.printStackTrace();

}

if((anArray[i])==42)

{

break;

}

System.out.print("n In loop"+i+"n");

i++;

}

//     System.out.print("n After coming out of loop "+i+"n");

for (int pos=0;pos<i;pos++)

{

System.out.println(anArray[pos]);

}  

}

}

You didn't read the bit I mentioned. The point is whatever you use, you should only create one such object on the standard input stream, not once every loop.

#include<stdio.h>

int main()

{

int t;

while(1)

{

scanf("%d",&t);

if(t==42||t>99)

break;

printf("%d",t);

}

return 0;

}

Its Showing correct Output on my PC

using System;
class Life_Universe_and_Everything
{
static void Main(string[] args)
{
int n=1, a;
Console.Write("How many numbers do you want to enter ?");
n = int.Parse(Console.ReadLine());
int[] array1 = new int[n];
for (int i = 0; i < n; i++)
{
a = int.Parse(Console.ReadLine());
if (a < 100)
array1[i] = a;
else
{
Console.WriteLine("Enter Only 1 or 2 Digit numbers");
i--;
}
}
for (int i = 0; i < n; i++)
{
if (array1[i] != 42)
Console.WriteLine(array1[i]);
else
i = n;
}
}
}

public class Main
{    private static int readInt() throws Exception
{    int i=0;
int r=0;
//while((i=System.in.read())!='n'&&i!='r');
while((i=System.in.read())!='n'&&i!='r')
{    r*=10;
r+=(i-'0');
}
return r;
}
public static void main(String[]arg)throws Exception
{    for(int i=0;(i=readInt())!=42;
System.out.println(i));
}
}

Why does this give a runtime error?

It runs correctly on my ubuntu 8.04 machine.

#include<stdio.h>
#include<stdlib.h>

int main() {
int i;
while(1) {
scanf("%d", &i);
if(i != 42)
printf("%dn", i);
else
exit(1);
}

}

Do you know what the exit function does? I suggest you read some C documentation on it, and/or read the FAQ.

//hello what is wrong with my code please help, they are giving compile error.

import java.util.Scanner;


public class Bruteforce {




public static void main(String[] args) {

Scanner input = new Scanner(System.in);



int i;

for(;;){
System.out.print("enter int number : n");

i=input.nextInt();
System.out.printf(" %d ", i );

if(i==42){
break;}
}
}

#include<iostream.h>

#include<conio.h>

void main()

{

int a[25],n;

cout<<"n Enter the no. of elements u want to enter:";

cin>>n;

for(int i=0;i<n;i++)

cin>>a[i];

i=0;

while(a[i]!=42)

{

cout<<a[i];

i++;

}

getch();

}

@Ritika:

I fear the solution is completely wrong!

You need to read the FAQ!

import java.util.Scanner;

public class BrutForce

{

public static void main(String... args)

{

Scanner input = new Scanner(System.in);

int number = 0;

while(true)

{

number = input,nextInt();

if (number == 42)  break;

System.out.println(number);

}

}

}

#include<stdio.h>

#include<conio.h>

#define pf printf

#define sf scanf

void main()

{

int a,i,n;

clrscr();

pf("nn PLZ enter how many times u want to keep entering the value n");

sf("%d",&a);

for(i=1;i<=a;i++)

{

pf("nenter the value but beware do not enter the value 42 or the program will terminatenn");

sf("%d",&n);

if(n==42)

{

pf("caution !!!! u have entered 42 as valuennnt the program will now terminatennpress any                                                                                                                               key to continuen");

ghetch();

break;

}

pf("nnthe entered value is ===> %dnn",n);

}// end of for

} // end of main

@Nilesh:

Please read FAQ!

help me with this IN C

if i use linkd list,time limit exceeds

if i use array i have to give array sze constant

Don't use either. Print each number as you read it. (See the FAQ if you don't know how your code is tested.)

public static void main(String[] args) {


Scanner input = new Scanner(System.in);



int i;



for(;;){
i=input.nextInt();
if(i!=42)
System.out.printf(" %d ", i );
else
break;
}

}



is this code ok?

#include<stdio.h>
int main()
{
int t;
while(1)
{
scanf("%d",&t);
if(t==42)break;
printf("%dn",t);
}
return 0;
}

#include<stdio.h>
void main()
{
int i,j,temp,c[99],a[99],b,d;
clrscr();
printf("Enter the no of inputs");
scanf("%d",&b);
printf("Enter the no one by one");
for(i=0;i<b;i++)
{
//printf("n");
scanf("%d",&a[i]);
}
for(i=0;i<b;i++)
{
if(a[i]!=42)
{
c[i]=a[i];
//printf("%d",a);
}
else
{
d=i;
break;
}
}
for(i=0;i<d;i++)
{
for(j=0;i<d;j++)
{
if(c[j]>c[i])
{
temp=c[j];
c[j]=c[i];
c[i]=temp;
}
}
}
for(i=0;i<d;i++)
printf("%dt",c[i]);
getch();
}

This program is running in my turbo c compiler but i cant submit can u help me please

#include<stdio.h>

int main()

{

int x;

for(;;)

{

scanf("%d",&x);

if(x>0&&x<100&&x!=42)

printf("%dn",x);

else

break;

}

return 0;

}

why the above code is being rejected?

#include "stdio.h"

int main(){

int i;

for(;;){

scanf("%d", &i);

if(i != 42){

printf("%dn", i);

} else {

return 0;

}

}

}

#include<stdio.h>

void main()

{

int arr[5],i;

printf("enter five intergersn");

for(i=0;i<5;i++)

{

scanf("%d",&arr[i]);

}

for(i=0;i<5;i++)

{

if(arr[i]==42)

break;

else

printf("%dn",arr[i]);

}

getch():

}

can someone please suggest what's wrong with my ans.

#include<stdio.h>

int main()

{

int a;

while(1)

{

scanf("%d",&a);

if(a==42)break;

printf("%dn",a);

}

return 0;

}

Okay, I uploaded my .java file and it told me that there were compile errors! I know that is not true because I compiled the program and ran it several times before I uploaded the file to your site.

I'm using JGrasp to write and compile my Java programs...is that the problem? Do I need to use some other method in order to have a successful upload??

I presume you've read the FAQ?

Yes, I've read through the FAQ but I'm a beginner programmer and the details of the FAQ are vague to me. I can't seem to figure out how your computer compiles the programs. I think I should just drop out of this until I've had a few years of programming experience. Although I was able to successfully get my program to function properly for a user, I am not able to figure out your compiling system...

Vague? It seems pretty specific. For example, under the 'Why do I get a compile error' section, it tells you your java class must be called Main. Yours isn't. It also tells you under the first section that you shouldn't be prompting the user for input in a dialog box, and in the second section how to test your code properly.

This is my java code.

/*

* To change this template, choose Tools | Templates

* and open the template in the editor.

*/

package codechef;

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

/**

*

* @author admin

*/

public class Main {

/**

* @param args the command line arguments

*/

public static void main(String[] args) throws IOException {

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

int input = Integer.parseInt(br.readLine());

while (input != 42) {

System.out.println(input);

input = Integer.parseInt(br.readLine());

}

}

}

class Life{
public static void main(String ar[])
 {

//command line argument for input

 for(int i=0;i<ar.length;i++)
  {
   if(Integer.parseInt(ar[i])==42)
   break;
   System.out.println(ar[i]);
  }

 }
}

admin i posted this following program as the solution to this problem.. it is working fine on my compiler but it is showing a run time error here.. can you please tell where the error is?

#include<stdio.h>
void main()
{
int num;
while(1)
{
scanf("%d",&num);
if(num==42)
break;
else
printf("n%d",num);
}
}

admin i submitted this code of mine as  a solution to this problem but it is showing some run time error n it is working fine on my compiler... kindly check where the problem actually exists..

#include<stdio.h>
void main()
{
int num;
while(1)
{
scanf("%d",&num);
if(num==42)
break;
else
printf("n%d",num);
}
}

Please read the FAQ.

did it in first try...felt great... awesome this night is of some worth today: :) time is 1:59 a.m.

i did it in first try.. felt great.. :)

My program running fine on my compiler whats wrong here

#include<iostream>
using namespace std;
int main()
{
int i=0;
for(;(cin>>i)&&i!=42;cout<<i);
}

i done with this problem.....

my question is how this program related with the life ,universe..blah blah

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

/**
 *
 * @author ASP.NET
 */
public class Main {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        int x = Integer.parseInt(br.readLine());
        if(x!=42)
            System.out.print(x);
    }

}

I am getting wrong answer in submission why???

Your program gives the wrong answer for the sample input. All it prints is 1.

#include<stdio.h>

int main()

{

int a;

while(1)

{

printf("%d",a);

scanf("%d",&a);

if(a=42)

break;

}

}

i m beginner help me out

#include<stdio.h>

#include<stdlib.h>

int main()

{

int a,n,i;

printf("enter numbers that u are interested ")

scanf("%d",&n)

for(i=0;i<n;i++)

scanf("%d",&a[i]);

for(i=0;i<n;i++)

{

if(a[i]==42)

exit(0);

else

printf("%d",a[i]);

}

}

#include<stdio.h>
main()
{
int a,b;
b=1;
while(b=1)
{   
printf("please enter the no.");
scanf("%d",&a);

if (a!=42)
{printf("tt%d",a);
}
else{
b=0;
break;
}
}
return 0;

}

#include<iostream.h>

#include<conio.h>

void main()

{

int a,b[100],p=0;

while(1)

{

cin>>a;

if(a==42)

break;

{

b[p]=a;

p++;

}

}

for(int c=0;c<p;c++)

cout<<b[c];

getch();

}

what's the problem with this code ??

gives me wrong answer

#include<iostream>

using namespace std;

int main()

{

int test[100],i=0;

for(i=0;i<100;i++)

{

cin>>test[i];

if(test[i]==42)

{

cin>>test[++i];

break;

}

}

int j=i;

for(i=0;i<j;i++)

cout<<test[i]<<endl;

return 0;

@dhruv

what's the problem with this code ??

gives me wrong answer

#include<iostream>

using namespace std;

int main()

{

int test[100],i=0;

for(i=0;i<100;i++)

{

cin>>test[i];

if(test[i]==42)

{

cin>>test[++i];

break;

}

}

int j=i;

for(i=0;i<j;i++)

cout<<test[i]<<endl;

return 0;

//its not neccessary to first print all input and then their respective output

you can do something like this..lets say user enter i/p x whose o/p is y

x

y(after pressing enter)

#include<stdio.h>

void main()
{
int i;

while(1)
{
scanf("%d",&i);
if (i==42)
break;
else
printf("%dn",i);
fflush(stdin);
}

}

-- I have submitted above program but i got run time error without fflush(stdin) and got compilation error with that statement.

-- As our program is checked by some software. It might be using predefined inputs files for testing our program. It might be storing output to some other temporary file. And then might be comparing that with some permanent files for specific inputs file. So, if this is the case then it should give correct result.

-- Can anybody help me to understand the reason of errors I got or otherwise tell me what I am missing who so ever has successfully submited this program.

#include<stdio.h>

void main()
{
int i;

while(1)
{
scanf("%d",&i);
if (i==42)
break;
else
printf("%dn",i);
fflush(stdin);
}

}

-- I have submitted above program but i got run time error without fflush(stdin) and got compilation error with that statement.

-- As our program is checked by some software. It might be using predefined inputs files for testing our program. It might be storing output to some other temporary file. And then might be comparing that with some permanent files for specific inputs file. So, if this is the case then it should give correct result.

-- Can anybody help me to understand the reason of errors I got or otherwise tell me what I am missing who so ever has successfully submited this program.

-- Is there any IDE which works similar to Software checking our problem.

//WHY IT IS RUNTIME ERROR?  I DID NOT GET............I APPRECIATE YOUR FEEDBACK..............

#include<stdio.h>

void main(){

int a[5];

int i;

for(i=0;i<5;i++){

scanf("%d",&a[i]);

}

//for comparision

for(i=0;i<5;i++){

if(a[i]==42)

break;

printf("n%d",a[i]);

}

}

#include<iostream.h>

#include<conio.h>

void main()

{

int i;

for(;;)

{

cin>>i;

if(i==42)

break;

cout<<i;

}

getch();

}

First Read FAQ!

PLEASE TELL...WHY THIS CODE IS NOT WORKING???

#include<stdio.h>

#include<stdlib.h>

typedef struct node

{

int no;

struct node *link;

}node;

main()

{

int num;

node *temp,*start,*temp1;

temp=(node *)malloc(sizeof(node));

start=temp;

do

{

scanf("%d",&num);

if(num==42)

{

temp==NULL;

break;

}

else

{

temp->no=num;

temp1=(node *)malloc(sizeof(node));

temp->link=temp1;

temp=temp1;

}

}while(1);

temp=start;

while(temp!=NULL)

{

printf("%dn",temp->no);

temp=temp->link;

}

}

i''ve submitted the correct code .....i've checked it twice but the submission is producing run time error....plz reply

This is my solution in Java

public class Life{

 public static void main(String[] args){

 java.io.BufferedReader in = new java.io.BufferedReader (new java.io.InputStreamReader (System.in));

 String str = in.readLine();

 while(!str.startsWith("42"))

 System.out.println(str);

 }

}

#include<stdio.h>
main()
{
int n,t;
while(t--)
{
scanf("%d",&n);
if (n==42)
{
break;
}
else
printf("%dn",n);
}

return 0;
}

The example was not clear enough first. :)

#include<stdio.h>
main()
{
int n,t;
while(t--)
{
scanf("%d",&n);
if (n==42)
{
break;
}
else
printf("%dn",n);
}

return 0;
}

import java.util.*;

class TEST

{

public static void main(String args[])

{

Scanner s =new Scanner(System.in);

int x=s.nextInt();

while(x!=42)

{

System.out.println(x);

x=s.nextInt();

}

System.exit(1);

}

}

why isnt this not being accepted...???

#include<conio.h>

#include<iostream.h>

main()

{

clrscr();

int a[5];

for(int i=0;i<5;i++)

{

cout<<"Enter The No."<<endl;

cin>>a[i];

}

for(int i=0;i<3;i++)

{

cout<<a[i]<<endl;

}

getch();

}

import java.util.*;

class A

{

Scanner in=new Scanner(System.in);

int e[]=new int[10];

public void setArray()

{

for (int i=0; i<10; i++)

{

e[i]=in.nextInt();

}

System.out.println("n");

}

public void getArray()

{

for(int i=0; i<10; i++)

{

if (e[i]==42)

{

break;

}

System.out.println(e[i]);

}

}

public static void main(String a[])

{

A w=new A();

w.setArray();

w.getArray();

}

}

Can someone explain how to write asm code for this problem?

Thanks

#include<stdio.h>
int num[2];

int main()
{  
int a;
int i;

i=0;
while(scanf("%d",&a)==1)
{
if(a == 42) break;
else num[i] = a;
i++;
}

for(i=0; i<sizeof(num); ++i)
{
if(num[i]== 0) break;
else printf("%dn",num[i]);
}

return 0;
}

why this code is not taken as the solution of this problem

Hey check me if i am wrong .....

The sample input output is displayed wrong...

it should be like this

Input: 4

Output: 4

Input: 56

Output: 56

Input: 32

Output: 32

Input: 87

Output: 87

Input: 42

right?

#include<conio.h>
#include<iostream.h>
void main()
{
int n;
cin>>n;
if(n!=42)
{

cout<<n;
}
getch();
}

#include<iostream.h>
void main()
{
int n;
cin>>n;
if(n!=42)
{

cout<<n;
}
getch();
}

hahaha!!!!

this is real crap...
this question's solution as submitted by other users is literally wrong..
bcoz

see the input in question:
"1

2
88
42
99

"

frm this it means that a user can enter a number beyond 42....

after that it would check uptil 42 and then it would print...

but most users have posted answers where you cannot enter a number after 42 , as it breaks from there and exits..
so the question is wrong

Can anyone help me out with this problem?

:: CODE STARTS ::

<?php

while (true)

{

$line = fgets(fopen ("php://stdin','r'"));

if(trim($line) != '42')

{

echo trim($line) . 'n';

}

else

{

break;

}

}

?>

:: CODE ENDS ::

I am getting "Time Limit exceeded" after I submit the above code.

Can anyone point out, how can I optimize the code to make it work before the defined time limit?

Thanks in advance.

Regards,
Michael.

Anyways, I solved it!!!

:: Optimized CODE STARTS ::

<?php

while (1)

{

$line = trim(fgets(STDIN));

if($line != '42')

{

fwrite(STDOUT, $line."n");

}

else

{

break;

}

}

?>

:: CODE ENDS ::

Regards,
Michael.

plc tell me what is wrong with this it gives run time error bt i cant figure it out.

#include <iostream>

using namespace std;

int main(void){

int inputNum = 0 , validater = 0;

while(true){

cin >> inputNum;

if(inputNum == 42)

validater = 1;

if(inputNum != 42 && validater == 0)

cout << inputNum << endl;

}

return 0;

}

plc tell me what is wrong with this it gives run time error bt i cant figure it out.

#include <iostream>

using namespace std;

int main(void){

int inputNum = 0 , validater = 0;

while(true){

cin >> inputNum;

if(inputNum == 42)

validater = 1;

if(inputNum != 42 && validater == 0)

cout << inputNum << endl;

}

return 0;

}

@Chaminda Sampath

in very 1st line...

->#include<iostream.h>

#include <stdio.h>

#include <conio.h>

void main()

{

int i=0;

while ( i!= 42)

{

scanf ("%d", &i);

printf ("%d", i);

}

getch();

clrscr();

}

import java.util.Scanner;

class BruteForce

{

 public static void main(String arg[])

{

int i=0;

int A[]=new A[99];

Scanner in=new Scanner(System.in);

System.out.println("enter any no in 2 digits max:");

while(i<=99)

{

if(A[i]!=42)

{

System.out.println(A[i]);

}

else

break;

}

}

}

#include<iostream.h>

main()

{

int a[5];

for(int i=0;i<5;i++)

{

cout<<"Enter the 2 digit no. "<<i<<endl;

cin>>a[i]

}

for(i=0;i<5;i++)

{

if(a[i]!=45)

{

cout<<a[i]<<endl;

}

else

return 0;

}

}

#include<stdio.h>

int main()

{

int x;

for(;;)

{

scanf("%d",&x);

if(x>0&&x<100&&x!=42)

printf("%dn",x);

else

break;

}

return 0;

}

//You should enter the number except the 42 then it will execute successfull

#include<stdio.h>
void main()

{

int x;

for(;;)

{

scanf("%d",&x);

if(x!=42)

printf("%dn",x);

else

break;

}

}

import java.util.*;
class BruteForce
{
public static void main(String []args)
{
Scanner kb=new Scanner(System.in);
int i,len=0,a[]=new int[30];
do
{
a[len]=kb.nextInt();
len=len+1;
}
while(a[len-1]!=42);
for(i=0;i<len-1;i++)
{
System.out.println(a[i]);
}
}
}

#include<iostream.h>

#include<conio.h>

int main()

{int a[100],i,ch;

{cout<<"enter the nos:n";

{

for(i=0;i<100;++i)

cin>>a[i];

if(a[i]==42)

break;

]

ch=i;

}

for(i=0;i<ch;++i)

cout<<"n"<<a[i];

getch();

}

#include<stdio.h>

#include<conio.h>

void main()

{

int a[100],i,n;

printf("enter the nos = ");

for(i=0;i<100;i++)

{

scanf("%d",&n)

if(n==42)

break;

a[i] = n;

}

n=i;

for(i=0;i<=n;++i)

printf("%dn"a[i]);

getch();

}

#include<iostream.h>

#include<conio.h>

void main()

{

clrscr();

int a,i=0;

while(i!=42)

cout<<i;

i++;

}

getch();

}

#include<iostream.h>

#include<conio.h>

void main()

{

clrscr();

int a,i=0;

while(i!=42)

{

cout<<i;

i++;

}

getch();

}

#include<stdio.h>

int main()

{

int i

while(i!=42)

{

printf("enter a two digit number");

scanf("%d",&i);

printf("%d",i);

}

return 0;

}

class number

{

public static void main(String []s)

{

s[]={1,2,88,42,77};

for(int i=0;i<=s.length-2;i++)

{

System.out.println(s);

}

}

}

using System;

using System.Collections.Generic;

using System.Linq;

using System.Text;

namespace democonsole

{

class Program

{

static void Main(string[] args)

{

int[] a = new int[5];

a[0] = 1;

a[1] = 2;

a[2] = 88;

a[3] = 42;

a[4] = 99;

System.Console.WriteLine("nn");

for (int i = 0; i < 4; i++)

{

if (a[i] != 42)

{

System.Console.WriteLine(a[i]);

}

else

break;

}

Console.ReadKey();

}

}

}

whats the error here mate any one

#include <stdio.h>

#include <stdlib.h>

int main()

{

int i;

for(;;)

{

scanf("%d", &i);

if(i != 42)

{

printf("%dn", i);

}

else

{

return 0;

}

}

system("PAUSE");

}

void main()

{

int i=0;

while(1)
{

printf("Enter your number");
scanf("%d",&i);

if(i==42)   
break;

else
printf("%d",i);   

}   



}

#include "stdio.h"

int main(){

int i;

for(;;){

scanf("%d", &i);

if(i != 42){

printf("%dn", i);

} else {

return 0;

}

}

}

#include<stdio.h>

#include<conio.h>

void main()

{

int a[10]={0},i=-1,j;

do

{

scanf("%d",&a[++i]);

}while(a[i]!=42);

for(j=0;j<i;j++)

printf("%d",a[j]);

getch();}

whats the difference in coding in turbo c++ and a gcc  compiler i am not used to gcc compiler what are the things that i should atleast know to code in gcc compiler and compile my code?

Hii....

I'm using Dev C++ for coding problems....

Which Language I should select from the drop down menu for submitting the code on my profile....

there's no option for DEV C++....

I've compiled the code on my PC successfully.....

Please help me out....

@Prerit Anwekar - GCC compiler is a Linux based editor for C++....

#include<stdio.h>

#include<conio.h>

void main()

{

int i;

printf("ENTER NUMBER = n");

scanf("%d",i);

while(1)

{

if(i!=42)

printf("%d",i);

else

break();

}

}

#include<stdio.h>

int main(void)

{

unsigned int num;
int n;

printf("Enter no of integer: ");
scanf("%d",&n);

for(int i=0i<n;i++)
{
printf("Enter the 2 digit positive no. :");
scanf("%d",&num[i]);
if(num[i]>99 | num[i]<0)
{
printf("Error in input");
exit(0);
}
}

for(i=0i<n;i++)
{
printf("Enter 2 digit positive no.");
scanf("%d",&num[i]);
if(num[i]==42)
break;
}
return(0);

}

#include<stdio.h>

int main()

{

int a;

for(;;)

{

cin>>a

if(a==42)

break;

else

cout<<a;

}

}

@Codechef, how do you check the Mem?

I've submitted the same code in C as others with 0M did. But it shows me 1.6M? Why?

Is this something to do with browsers?

Please help, I've competition on 20th april and this will really help me.

import java.io.*;

public class NewClass

{

public static void main(String args[])throws IOException

{

int a;

do{

DataInputStream in=new DataInputStream(System.in);

a=Integer.parseInt(in.readLine());

System.out.println(a);

} while (a != 42);

}

}

#include<stdio.h>
#include<conio.h>
void main()
{
int n;
clrscr();
printf("PLEASE ENTER ANY INTEGER NUMBER OF ONE OR TWO DISITS ");
do
scanf("%d",&n);
while(n!=42);
printf("nn42 found!!!nnPLEASE PRESS ANY KEY TO EXIT");
getch();
}

puts "Input integers of one or two digits separated by space."
input = gets.chomp
input.split(" ").each do |n|
exit if n.to_i == 42
puts n
end

ARGV.each do |n|
puts n
exit if n == 42
end

//Program for inputing 10 numbers at a time
//it terminates and print the entered numbers before the digit 42
import java.util.Scanner;

public class Test1
{
static Scanner sn=new Scanner(System.in);


public static void main(String[] args)
{
int[] arr=new int[10];
int num; 
System.out.println("Enter two digit numbers:");
{
num=(int)Integer.parseInt(""+sn.next());
for(int i=0;i<arr.length;i++)
{
if(num!=42)
{
arr[i]=num;
num=(int)Integer.parseInt(""+sn.next());
}
else
break;
}
System.out.println("Entered numbers are:");
for(int i=0;i<arr.length;i++)
{
if(arr[i]!=42) 
{

if(arr[i]==0)
{
break;
}
System.out.println(arr[i]);
}  
else
{ 
break;
}

}
}
}
}
//It's Hp

import java.util.*;

public class BruteForce

{

public static void main(String s[])

{

Scanner sc=new Scanner(System.in);

int i=0;

while(1)

{

i=sc.nextInt();

if(i==42)

break;

System.out.println(i);

}

}

}

this is the correct code in C

written in DEV C++ Compiler

frist time it wsnt accepted because i didnt choose the Language C in the submit page, so beaware..

#include<stdio.h>
//#include<conio.h>

int main()

{
int i;

while (scanf("%d",&i))
{
if (i==42)
{
break;
}
else
{
printf("%dn",i);
}
}

//getch();
return 0;
}

#include<stdio.h>
int main()
{
int a;
for(;;)
{
scanf("%d",&a);
if(a!=42)
{
printf("%dn",a);
}
else
{
break;
}
}
}

WHATS WRONG WITH IT IAM GETTING RUNTIME ERROR

#include <stdio.h>

int main()

{

int i =0;

while(i != 42)
{
    scanf("%d",  &i);
    printf("%d", i);
}

}

#include <stdio.h>

void main()
{
int i = 42;
scanf("%d", &i);
while( i != 42)
{
printf("%dn", i);
scanf("%d", &i);
}
}