Gravel

Problem code: SPREAD

All submissions for this problem are available.

Bob has n heap(s) of gravel (initially there are exactly c piece(s) in each). He wants to do m operation(s) with that heaps, each maybe:

adding pieces of gravel onto the heaps from u to v, exactly k pieces for each,
or querying "how many pieces of gravel are there in the heap p now?".

Request

Help Bob do operations of the second type.

Input

The first line contains the integers n,m,c, respectively.
m following lines, each forms:
- S u v k to describe an operation of the first type.
- Q p to describe an operation of the second type.

(Each integer on a same line, or between the characters S, Q and the integers is separated by at least one space character)

Output

For each operation of the second type, output (on a single line) an integer answering to the respective query (follows the respective Input order).

Example

Input:

Output:

0
1
2

Limitations

0<n?10⁶
0<m?250 000
0<u?v?n
0?c,k?10⁹
0<p?n

Author:	anhdq
Date Added:	5-05-2010
Time Limit:	2 sec
Source Limit:	50000 Bytes
Languages:	ADA, ASM, BASH, C, C99 strict, CLOJ, CPP 4.0.0-8, CPP 4.3.2, CS2, D, F#, FORT, GO, ICON, JAR, JAVA, LISP clisp, LISP sbcl, LUA, NEM, NICE, PAS fpc, PAS gpc, PERL, PERL6, PHP, PIKE, PYTH, PYTH 3.1.2, RUBY, SCM guile, SCM qobi, ST, TCL

Submit

Comments

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Why am i getting wrong

singh_637 @ 12 Apr 2011 11:31 PM

Why am i getting wrong answer?

Could you please give me more test cases?

#include<stdio.h>

long long int a[1000050]={0};
long long int result,result1,result2,sum=0;

void scan(char str[])
{
int i=0,m;
result=0;
result1=0;
result2=0;
sum=0;
i=2;
while(str[i]!='')
{

switch(str[i])
{
case '0': m=0; break;
case '1': m=1; break;
case '2': m=2; break;
case '3': m=3; break;
case '4': m=4; break;
case '5': m=5; break;
case '6': m=6; break;
case '7': m=7; break;
case '8': m=8; break;
case '9': m=9; break;
}
if(str[i+1]==' ' || str[i+1]=='')
{

sum=sum*10+m;
result=sum;
i++;
sum=0;
goto X;
}
else
{
sum=sum*10+m;
goto Y;
}
X:while(str[i]!='')
{
switch(str[i])
{
case '0': m=0; break;
case '1': m=1; break;
case '2': m=2; break;
case '3': m=3; break;
case '4': m=4; break;
case '5': m=5; break;
case '6': m=6; break;
case '7': m=7; break;
case '8': m=8; break;
case '9': m=9; break;
}
if(str[i+1]==' ')
{
sum=sum*10+m;
result1=sum;
i+=2;
sum=0;
goto S;
}
else
{
sum=sum*10+m;
goto Z;
}
S:while(str[i]!='')
{
switch(str[i])
{
case '0': m=0; break;
case '1': m=1; break;
case '2': m=2; break;
case '3': m=3; break;
case '4': m=4; break;
case '5': m=5; break;
case '6': m=6; break;
case '7': m=7; break;
case '8': m=8; break;
case '9': m=9; break;
}
if(str[i+1]=='')
{
sum=sum*10+m;
result2=sum;
i++;
break;
}
else
{
sum=sum*10+m;
goto T;
}
T:i++;
}
Z:i++;
}
Y:i++;
}
}
int main()
{
long long int n,test;
long long int c;

int j;
char str[80]="";
scanf("%lld%lld%lld",&n,&test,&c);
for(j=0; j<=n; j++)
a[j]=c;
while(test--)
{
printf("n");
fflush(stdin);
gets(str);
scan(str);
if(str[0]=='Q')
printf("%lld",a[result]);
else
{
for(j=result; j<=result1; j++)
{
a[j]+=result2;
}
}
}

return 0;
}

This program is producing

singh_637 @ 13 Apr 2011 11:10 PM

This program is producing correct output in my computer but it is showing wrong output on this website.

Please tell me why?

#include<stdio.h>
#define max 1000050
long long a[max];

long long int result,result1,result2,sum=0;

void scan(char str[])
{
int i=0,m,flag=0;
result=0;
result1=0;
result2=0;
sum=0;
i=2;
while(str[i]!='')
{

switch(str[i])
{
case '0': m=0; break;
case '1': m=1; break;
case '2': m=2; break;
case '3': m=3; break;
case '4': m=4; break;
case '5': m=5; break;
case '6': m=6; break;
case '7': m=7; break;
case '8': m=8; break;
case '9': m=9; break;
}
if(str[i+1]==' ' || str[i+1]=='')
{

sum=sum*10+m;
result=sum;
i++;
flag=0;
sum=0;
goto X;
}
else
{
sum=sum*10+m;
goto Y;
}
X:while(str[i]!='')
{
if(flag==0)
{
i++;
flag=1;
}
switch(str[i])
{
case '0': m=0; break;
case '1': m=1; break;
case '2': m=2; break;
case '3': m=3; break;
case '4': m=4; break;
case '5': m=5; break;
case '6': m=6; break;
case '7': m=7; break;
case '8': m=8; break;
case '9': m=9; break;
}
if(str[i+1]==' ')
{
sum=sum*10+m;
result1=sum;
i+=2;
sum=0;
goto S;
}
else
{
sum=sum*10+m;
goto Z;
}
S:while(str[i]!='')
{
switch(str[i])
{
case '0': m=0; break;
case '1': m=1; break;
case '2': m=2; break;
case '3': m=3; break;
case '4': m=4; break;
case '5': m=5; break;
case '6': m=6; break;
case '7': m=7; break;
case '8': m=8; break;
case '9': m=9; break;
}
if(str[i+1]=='')
{
sum=sum*10+m;
result2=sum;
i++;
break;
}
else
{
sum=sum*10+m;
goto T;
}
T:i++;
}
Z:i++;
}
Y:i++;
}
}

int main()
{
long long int n,test;
long long int c;

int j;

scanf("%lld%lld%lld",&n,&test,&c);
for(j=0; j<=n; j++)
a[j]=c;
while(test--)
{
char str[80]="";

fflush(stdin);

gets(str);
scan(str);
if(str[0]=='Q')
printf("%lld",a[result]);
else
{
for(j=result; j<=result1; j++)
{
a[j]+=result2;
}
}
}

return 0;
}

I am getting runtime error

sakuag333 @ 18 Apr 2011 12:31 AM

I am getting runtime error again and again.

i am using segment tree.

the code is running fine on my system with even n=100000.

@sakuag333 ur getting runtime

KK123 @ 19 Jul 2011 01:01 AM

@sakuag333 ur getting runtime error bcoz may be ur using smaller array.... try it again increasing the size of the array...

Hi I am getting correct

suneelprakash @ 19 Jan 2012 01:16 PM

Hi I am getting correct output but time limit exceeded But still i can see some submissions where aircube 178.6M 41.97 JAVA View Solution 41.97 is timelimit How can i know the time taken for it.

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