Last Digit SumProblem code: LASTDIG |
All submissions for this problem are available.
For a non-negative integer N, define S(N) as the sum of the odd digits of N plus twice the sum of the even digits of N. For example, S(5)=5, S(456)=2*4+5+2*6=25, and S(314159)=3+1+2*4+1+5+9=27. Define D(N) as the last digit of S(N). So D(5)=5, D(456)=5, and D(314159)=7. Given 2 non-negative integers A and B, compute the sum of D(N) over all N between A and B, inclusive.
Input
Input will begin with an integer T, the number of test cases. T lines follow, each containing 2 integers A and B.
Output
For each test case, output a single integer indicating the corresponding sum.
Sample Input
3 1 8 28 138 314159 314159
Sample Output
36 495 7
Constraints
- T ≤ 1000
- 0 ≤ A ≤ B ≤ 400,000,000
| Author: | pieguy |
| Tester: | chmel_tolstiy |
| Editorial | http://discuss.codechef.com/problems/LASTDIG |
| Date Added: | 2-09-2011 |
| Time Limit: | 1 sec |
| Source Limit: | 50000 Bytes |
| Languages: | ADA, ASM, BASH, BF, C, C99 strict, CAML, CLOJ, CLPS, CPP 4.0.0-8, CPP 4.3.2, CS2, D, ERL, FORT, FS, GO, HASK, ICK, ICON, JAR, JAVA, JS, LISP clisp, LISP sbcl, LUA, NEM, NICE, NODEJS, PAS fpc, PAS gpc, PERL, PERL6, PHP, PIKE, PRLG, PYTH, PYTH 3.1.2, RUBY, SCALA, SCM guile, SCM qobi, ST, TCL, TEXT, WSPC |
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plz xplain any one
suppose A=1 and B=8 than in
A=1,2,3,4,5,6,7,B=8 find
how does 28 138 become 495?
@anyone can anyone explain
1537369 can yu pls email the
@admin what is wrong
I have no idea why i'm
why error (compile )time is