/*
  Beautiful Codes are MUCH better than 'Shorter' ones !
user  : triveni
date  : 21/02/2018
time  : 22:45:59
*/
#include <bits/stdc++.h>

using namespace std;

#define      pii               std::pair<int,int>
#define      vi                std::vector<int>
#define      sz(v)             (int)(v.size())
#define      mp(a,b)           make_pair(a,b)
#define      pb(a)             push_back(a)
#define      each(it,s)        for(auto it = s.begin(); it != s.end(); ++it)
#define      rep(i, n)         for(int i = 0; i < (n); ++i)
#define      all(v)            v.begin(), v.end()
#define      scan(n)           scanf("%d", &n)
#define      scan2(n, m)       scanf("%d%d", &n, &m)
#define      pin(n)            printf("%d\n",n)
#define      pis(n)            printf("%d ",n)
#define      pll(n)            printf("%lld\n", n)
#define      X                 first
#define      Y                 second

typedef long long ll;
ll mod = 1000000007;

inline int pow_(ll a, int n, int p=mod){
int r=1;while(n){if(n&1)r=r*a%p;n>>=1;a=a*a%p;}return r;}
inline int inv_(int a) {return pow_(a, mod-2, mod);}
inline int add(int a, int b){a+=b;if(a>=mod)a-=mod;return a;}
inline void adds(int& a, int b){a+=b;if(a>=mod)a-=mod;}
inline int mul(int a, int b){return a*1ll*b%mod;}
inline void muls(int& a, int b){a=a*1ll*b%mod;}
inline int sub(int a, int b){a-=b;if(a<0)a+=mod;return a;}

char toChar(int c){
	return c + '0';
}

int getInt(char endChar) {
	int x = 0;
	char ch = getchar();
	while(ch >= '0' && ch <= '9') {
		x = x * 10 + ch - '0';
		ch = getchar();
	}
	assert(ch == endChar);
	return x;
}

int main()
{
	int T = getInt('\n');
	assert(1 <= T && T <= 10);
	while(T--) {
		int n = getInt('\n');
		assert(1 <= n && n <= 100000);
		ll totalLoss = 0;
		double ansL = 0;
		rep(i, n) {
			int p = getInt(' '), q = getInt(' '), d = getInt('\n');
			// scan2(p, q);
			// scan(d);
			assert(1 <= p && p <= 100);
			assert(1 <= q && q <= 100);
			assert(0 <= d && d <= 100);
			double newCost = p; newCost += newCost * d / 100.0;
			newCost -= newCost * d / 100.0;
			ansL += (p - newCost) * q;
			p *= 10000;
			totalLoss += p * q;
			p += p / 100 * d;
			p -= p / 100 * d;
			totalLoss -= p * q;
		}
		totalLoss *= 100;
		// totalLoss += 9999;
		string ans;
		rep(i, 6) {
			ans += toChar(totalLoss % 10);
			totalLoss /= 10;
		}
		ans += '.';
		ans += toChar(totalLoss % 10);
		totalLoss /= 10;
		while(totalLoss > 0) {
			ans += toChar(totalLoss % 10);
			totalLoss /= 10;
		}
		reverse(all(ans));
		// cout << ans << "\n";
		printf("%.10lf\n", ansL);
	}
	return 0;
}