/* AUTHOR:hruday pabbisetty NIT ROURKElA */ #include #include using namespace std; using namespace std::tr1; #define opt ios_base::sync_with_stdio(0) #define lli long long int #define ulli unsigned long long int #define I int #define S string #define D double #define rep(i,a,b) for(i=a;ib;i--) #define in(n) scanf("%lld",&n) #define in2(a,b) scanf("%lld %lld",&a,&b) #define in3(a,b,c) scanf("%lld %lld %lld",&a,&b,&c) #define out(n) printf("%lld\n",n) #define inu(a) scanf("%lld",&a) #define outu(a) printf("%llu",a) #define ins(s) scanf("%s",&s) #define outs(s) printf("%s",s) #define mod 1000000007 #define inf 100000000000000 typedef long long ll; typedef pair plli; typedef vector vlli; typedef vector vulli; typedef vector vll; typedef vector vs; typedef vector vplli; #define MM(a,x) memset(a,x,sizeof(a)); #define ALL(x) (x).begin(), (x).end() #define P(x) cerr<<"{"#x<<" = "<<(x)<<"}"< "#b": "<<1000*(b-a)/CLOCKS_PER_SEC<<"ms}\n"; #define UN(v) sort(ALL(v)), v.resize(unique(ALL(v))-v.begin()) #define mp make_pair #define pb push_back #define f first #define s second #define sz() size() #define nl cout<<"\n" #define MX1 100005 #define MX2 1000005 #define bs binary_search #define lb lower_bound #define ub upper_bound lli dx[]={0,0,-1,1}; lli dy[]={1,-1,0,0}; lli power(lli a,lli b) { lli value; if(b==0) { return 1; } else if(b%2==0) { value=power(a,b/2)%mod; return(value*value)%mod; } else { value=power(a,b/2)%mod; return ((a*value)%mod*(value))%mod; } } lli ans[1000005],diamonds[2000005],prefix_diamonds[2000005]; lli diamonds_in_room(lli n) { lli a[2]={0}; while(n) { a[n%2]+=n%10; n/=10; } return abs(a[0]-a[1]); } int main() { #ifndef ONLINE_JUDGE freopen("input5.txt","r",stdin); freopen("output5.txt","w",stdout); #endif*/ opt; lli i; rep(i,2,2000001) { diamonds[i]=diamonds_in_room(i);//stores the diamonds present in room with number i } rep(i,2,2000001) { prefix_diamonds[i]=prefix_diamonds[i-1]+diamonds[i];//stores the sum of diamonds present in all the rooms with number less than or equal to i } rep(i,1,1000001) { ans[i]=ans[i-1]; ans[i]+=2*(prefix_diamonds[2*i-1]-prefix_diamonds[i]);//calculating answer for i from i-1 using the recurrence relation. ans[i]+=diamonds[2*i]; } lli t; cin>>t; while(t--) { lli n; cin>>n; cout<