/*
 *
 ********************************************************************************************
 * AUTHOR : Vijju123                                                                        *
 * Language: C++14                                                                          *
 * Purpose: -                                                                               *
 * IDE used: Codechef IDE.                                                                  *
 ********************************************************************************************
 *
 Comments will be included in practice problems if it helps ^^
 */
 
 
 
#include <iostream>
#include<bits/stdc++.h>
using namespace std;
 
 
int main() {
	// your code goes here
	#ifdef JUDGE
    freopen("Input.txt", "rt", stdin);
    freopen("Diff.txt", "wt", stdout);
    #endif
	ios_base::sync_with_stdio(0);
	cin.tie(NULL);
	cout.tie(NULL);
	int t;
	cin>>t;
	cout.precision(3);
	assert(1<=t and t<=100000);
	while(t--)
	{
	    int n,s,y;
	    cin>>n>>s>>y;
	    assert(1<=n and n<=10 and 1<=s and s<=10 and 1<=y and y<=1000);
	    int i;
	    int v[n],d[n],p[n],c[n];
	    for(i=0;i<n;i++)
	    {
	        cin>>v[i];//An attempt to read input is made here :3
	        assert(1<=v[i] and v[i]<=200);
	    }
	    for(i=0;i<n;i++)
	    {
	        cin>>d[i];
	        assert(d[i]==0 or d[i]==1);
	    }
	    for(i=0;i<n;i++)
	    {
	        cin>>p[i];
	        assert(abs(p[i])<=1000000000);
	    }
	    for(i=0;i<n;i++)
	    {
	        cin>>c[i];
	        assert(1<=c[i] and c[i]<=1000);
	    }
	    long double ans=0,del=0.000001;
	    for(i=0;i<n;i++)
	    {
	        int back=c[i]*-1*(d[i]==0?-1:1)+p[i];//Co-ords of back of the car at t=0
	        long double backThen=back+(ans+1.0*y/s)*v[i]*(d[i]==0?-1:1);//Co-ords of current back of car
	        
	        if( (d[i]==1 and back>del) or (d[i]==-1 and back<-del) or(abs(back)<ans*v[i]+del))
	        {
	            //If car has already passed, either since t=0 or by the time chef reaches the lane
	            ans+=1.0*y/s;
	        }
	        else if((d[i]==1 and backThen<-del and backThen+c[i]<-del) or (d[i]==0 and backThen>del and backThen-c[i]>del))
	        {
	            //If car cannot reach by the time Chef crosses the lane.
	            ans+=1.0*y/s;
	        }
	        else
	        {
	            //Chef must wait for car to pass + Time taken to cross the lane
	            ans=ans+1.0*(abs(back)-v[i]*ans*1.0)/v[i];
	            ans+=1.0*y/s;
	        }
	    }
	    cout<<fixed<<setprecision(3)<<ans<<endl;
	}
 
	return 0;
}