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Home » Compete » Manthan 2010
Try your hand at one of the practice
                 problems, and submit your solution in the language of your choice
                 (our judge accepts solutions in over 35+ languages). Receive points,
                 and move up through the CodeChef ranks. Get better, and better prepare
                 yourself for the competitions
NameCodeSuccessful SubmissionAccuracy
DecryptionCF01249.45
Edit DistanceCF0283.83
Travel PlanCF031657.95
GCRDCF0400

Rules:

  • Contest problems will become visible on 28th March 18:00 IST and last until 29th March at 00:00 IST.
  • The contest will consist of 6 to 10 problems of varying difficulty.
  • Teams are ranked according to number of problems solved. Total Submission Time for all the correctly solved problems will be considered for tie breaking.
  • Incorrect submissions result in a penalty of 20 minutes.
  • This is a team based contest (up to 3 participants) you must register your team by March 28th 06:00 pm IST to participate (see the registration link below).
  • Anyone can participate but only teams which have registered for Manthan at Codefest will only be eligible for prizes.

Registration:

  • You can register for this contest at MANTH10 Registration Page (you must be logged in before registering).
  • Create your Team at Codefest for Manthan through Codefest Teams Page.
  • You can get more information about team contests here.

For any queries, email at codefest@itbhu.ac.in or post your query at Manthan Forum.


REGISTERED TEAMS:

167

 

RESULTS

  • Global
  • Eligible
Programming Competition Fetching successful submissions

External Contest

Please Note: This is an external contest. The problems and the content of this contest have not been created by CodeChef. CodeChef is only serving as the technical platform on which the contest is hosted. In order to report copyright violations send in an email to copyright@codechef.com .

RECENT ACTIVITY


Fetching recent activity

RECENT COMMENTS

11:55 PM Mar 28th: ankit_agrawal commented on GCRD: good...go to sleep..
11:54 PM Mar 28th: . commented on Decryption: titan, what is the name of your team? I also had (well, probably still have) the ...
11:49 PM Mar 28th: ForEver commented on GCRD: What a pity , and what a great thing! I study Matrix during the past 3 hours and ...
11:44 PM Mar 28th: manthan commented on GCRD: Yes, after reviewing the question statement again, we conclude that there may be m...
11:35 PM Mar 28th: ForEver commented on GCRD: I also think the answer are not unique..
11:24 PM Mar 28th: contest_crasher commented on GCRD: @CodeFest: Even if the greatest common right divisor is unique, X and Y are defini...
11:23 PM Mar 28th: Anton_Lunyov_MANTH10 commented on GCRD: May be we need to find upper-triangular GCRD with elements on diagonal d[1],d[2],....
10:49 PM Mar 28th: origamy commented on Decryption: hey, i cant submit any solution. there is no submit button for submission althoug...
10:48 PM Mar 28th: manthan commented on GCRD: GCRD(V1, V2) is a common right divisor of V1 and V2 (that is, V1 = W1*GCRD(V1, V2)...
10:19 PM Mar 28th: manthan commented on Travel Plan: The ScoreBoard will be updated tomorrow. The inconsistency is due to rejudging. F...

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