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Home » Compete » November Cook-Off » Moving Coins

Moving Coins

Problem code: MVCOIN

  • All Submissions

All submissions for this problem are available.

There is a line with 1000 cells numbered from 1 to 1000 from left to right and N coins placed on it. Coin i is placed at cell Xi, and no two coins are placed at the same cell.

Bob would like to move the coins to the N leftmost cells of the line. To do this, he is allowed to take a coin from any cell T and move it to cell T-j, where j is an integer between 1 and K, inclusive. This action is possible only if:

  • cell T-j actually exists and doesn't contain a coin;
  • each of the cells T-j+1, ..., T-1 contains a coin.

One coin movement takes exactly one second. Find the smallest time in which Bob can achieve his goal.

Input

The first line of the input file contains one integer T -- the number of test cases (no more than 10). Then T test cases follow, and every test case is described by two lines: the first of them contains two integers N and K (1 <= N, K <= 1000), the second of them contains N integers X1, ..., XN in strictly increasing order (1 <= Xi <= 1000).

Output

For each test case output one line containing the requested minimal time for Bob to put all the coins to the left side of the line.

Example

Input:
2
3 2
2 4 7
5 3
1 2 3 4 5

Output:
5
0

Explanation:
In the first example Bob can move the coin from cell 7 consequently to cells 6, 5, 3 and 1, then move the coin from cell 4 to cell 3. In the second example there is nothing to move.


Author: gennady.korotkevich
Date Added: 4-11-2011
Time Limit: 1 sec
Source Limit: 50000 Bytes
Languages: ADA, ASM, BASH, BF, C, C99 strict, CAML, CLOJ, CLPS, CPP 4.0.0-8, CPP 4.3.2, CS2, D, ERL, F#, FORT, GO, HASK, ICK, ICON, JAR, JAVA, JS, LISP clisp, LISP sbcl, LUA, NEM, NICE, PAS fpc, PAS gpc, PERL, PERL6, PHP, PIKE, PRLG, PYTH, PYTH 3.1.2, RUBY, SCALA, SCM guile, SCM qobi, ST, TCL, TEXT, WSPC


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Comments

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For first test case, will it

navinag @ 20 Nov 2011 09:49 PM
For first test case, will it be not, 7 to 5,3,1 then 4 to 3 in total 4 steps. Correct me if I am wrong.

@navinag. We can't move 7

anton_adm @ 20 Nov 2011 09:52 PM
@navinag. We can't move 7 directly to 5 since in 6 there is no coin.

For 4 steps we can move 7 to

ibmtp @ 20 Nov 2011 10:16 PM
For 4 steps we can move 7 to 6,5,3 then move 4 to 1. Am i wrong?

shouldnt the 1st one be done

diakatana @ 20 Nov 2011 10:17 PM
shouldnt the 1st one be done in 4steps. 7 to 6,5,3. 4 to 1

We can't move 4 to 1 since k

anton_adm @ 20 Nov 2011 10:20 PM
We can't move 4 to 1 since k is only 2. So from 4 we can move coin only to 3 or 2 if it is possible.

0101001 010101 01011 01110 11

mayank.punetha @ 20 Nov 2011 10:56 PM
0101001 010101 01011 01110 11100 4 steps??

kk got it

mayank.punetha @ 20 Nov 2011 10:57 PM
kk got it

why wont he directly move

supan51191 @ 20 Nov 2011 11:11 PM
why wont he directly move from 7 to 5 firstly ?

@supan51191. Read carefully

anton_adm @ 20 Nov 2011 11:14 PM
@supan51191. Read carefully this sentence "each of the cells T-j+1, ..., T-1 contains a coin."

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